• Log in with Facebook Log in with Twitter Log In with Google      Sign In    
  • Create Account
  LongeCity
              Advocacy & Research for Unlimited Lifespans

Photo
- - - - -

Methylene Blue dilution

methylene blue

  • Please log in to reply
60 replies to this topic

#31 Declmem

  • Guest
  • 315 posts
  • 11 ₮

Posted 18 October 2009 - 08:52 PM

For those of you who have 2.3% bottles like me, dilute 1ml of water with 19.1ml (actually 19.16) of water for the same effect. :p

Here's how I'm calculating this: (disclaimer: I'm no mathematician. could be totally off on this)

1ml = 1gram

given 2.3% solution, 1gram = 0.023 grams of actual MB, or 23mg, or 23,000mcg

since there are 20 drops per milliliter, 23,000/20 = 1150
so, 1drop = 1150mcg of MB

since our goal is 60mcg, 1150/x = 60, or 1150/60, which = 19.16

If there are any mathematicians here and I'm being completely stupid about this, please do tell me.

#32 qemist

  • Guest
  • 36 posts
  • 3 ₮

Posted 19 October 2009 - 04:02 AM

You can buy 50g of the powder on ebay for less than $10. That's 136 year's worth, if you take a generous 1mg per day.

Edited by qemist, 19 October 2009 - 04:02 AM.


sponsored ad

  • Advert
Click HERE to rent this advertising spot for SUPPLEMENTS (in thread) to support LongeCity (this will replace the google ad above).

#33 tritium

  • Guest
  • 384 posts
  • 70 ₮

Posted 19 October 2009 - 04:04 AM

From http://en.wikipedia..../Methylene_blue Molar mass=319.85 g/mol

2.303%=2.303g solute / 100mL solution = 2.303g / .1L = (23.03g / 1L) * (1mol/319.85g) = 2303/3985 moles per liter of solution = initial molarity = m1

According to http://www.novalek.c...easurements.htm 1 drop=0.05ml

Therefore for a 60mcg solution,

60mcg/.05mL = 6.0*10^-5g / 5.0*10^-5 L = [(6/5g)/L]*[1mol/319.85g] = 24/6397 moles per liter of solution = final molarity = m2

The dillution equation is m1v1=m2v2 where m1 is the initial molarity, m2 is the final molarity, v1 is the initial volume and v2 is the final volume. M1 and M2 are constant, so you can calculate the final volume given an initial volume.

For example 1/4 teaspoon of 2.303% MB = 0.0012322304L
The final volume = v2 = m1v1/m2 = (2303/31985)(.0012322304L)/(24/6397) = 0.02364855509 L
The amount of water needed is 0.02364855509 L - 0.0012322304L = 0.02241632469L ~ 22.4ml

In summary,
1/4 teaspoon Methylene Blue mixed with 22.4ml water = 1 drop containing 60mcg solution.

#34 tritium

  • Guest
  • 384 posts
  • 70 ₮

Posted 19 October 2009 - 05:48 AM

Here is another way of doing it.
Suppose you have a container with 1L of pure water. You pour Methylene Blue with a concentration of 0.02303 grams per liter at a rate of 1 ml per second. The solution is kept thoroughly mixed and drains from the tank at the same rate. The following procedure can be used to determine the concentration after 5 seconds:

dy/dt = rate in – rate out
rate in = 0.02303g/l * 0.001L/s = .00002303g/s
rate out = y(t) g/l * .001L/s = y(t)/1000 g/s
dy/dt = 0.00002303-y(t)/1000 = .02303-y(t)/1000

Solving this differential equation by the separation of variables method:
∫dy/.02303-y = ∫ dt/1000
-ln|.02303-y| = t/1000 + C
y(0) = 0
C = -ln(.02303)
-ln|.02303-y|=t/1000 – ln(.02303)
y(t)=.02303-.02303e^(-t/1000)
y(5)=.0001*100 = .01 = 1%

Therefore, after adding Methylene Blue at a rate of 1 ml per second for 5 seconds yields a concentration of about 1% in a 1 liter container.

Edited by tritium, 19 October 2009 - 05:50 AM.

  • dislike x 1

#35 Gerald W. Gaston

  • Guest
  • 529 posts
  • 58 ₮
  • Location:USA

Posted 19 October 2009 - 06:09 AM

Here is another way of doing it.
Suppose you have a container with 1L of pure water. You pour Methylene Blue with a concentration of 0.02303 grams per liter at a rate of 1 ml per second. The solution is kept thoroughly mixed and drains from the tank at the same rate. The following procedure can be used to determine the concentration after 5 seconds:

dy/dt = rate in – rate out
rate in = 0.02303g/l * 0.001L/s = .00002303g/s
rate out = y(t) g/l * .001L/s = y(t)/1000 g/s
dy/dt = 0.00002303-y(t)/1000 = .02303-y(t)/1000

Solving this differential equation by the separation of variables method:
∫dy/.02303-y = ∫ dt/1000
-ln|.02303-y| = t/1000 + C
y(0) = 0
C = -ln(.02303)
-ln|.02303-y|=t/1000 – ln(.02303)
y(t)=.02303-.02303e^(-t/1000)
y(5)=.0001*100 = .01 = 1%

Therefore, after adding Methylene Blue at a rate of 1 ml per second for 5 seconds yields a concentration of about 1% in a 1 liter container.


As nice as this looks, I don't think it will directly help them figure out how to dilute a percent solution. :p

Edited by frankbuzin, 19 October 2009 - 06:10 AM.


#36 Gerald W. Gaston

  • Guest
  • 529 posts
  • 58 ₮
  • Location:USA

Posted 19 October 2009 - 07:38 AM

From http://en.wikipedia..../Methylene_blue Molar mass=319.85 g/mol

2.303%=2.303g solute / 100mL solution = 2.303g / .1L = (23.03g / 1L) * (1mol/319.85g) = 2303/3985 moles per liter of solution = initial molarity = m1

According to http://www.novalek.c...easurements.htm 1 drop=0.05ml

Therefore for a 60mcg solution,

60mcg/.05mL = 6.0*10^-5g / 5.0*10^-5 L = [(6/5g)/L]*[1mol/319.85g] = 24/6397 moles per liter of solution = final molarity = m2

The dillution equation is m1v1=m2v2 where m1 is the initial molarity, m2 is the final molarity, v1 is the initial volume and v2 is the final volume. M1 and M2 are constant, so you can calculate the final volume given an initial volume.

For example 1/4 teaspoon of 2.303% MB = 0.0012322304L
The final volume = v2 = m1v1/m2 = (2303/31985)(.0012322304L)/(24/6397) = 0.02364855509 L
The amount of water needed is 0.02364855509 L - 0.0012322304L = 0.02241632469L ~ 22.4ml

In summary,
1/4 teaspoon Methylene Blue mixed with 22.4ml water = 1 drop containing 60mcg solution.



Its after 3am here... didn't look at the numbers but assuming all correct then your summary seems to be misstated (in the sense that you seem to be saying all that final solution only yields 1 drop). When from your numbers it appears that the final volume = 0.02364855509 L = ~ 23.6mL and with ~20 metric drops/mL you should have: ~472 drops @ 60mcg/drop

For simplicity and if 1metric drop = 0.05mL = 0.00005L ... Then using the rest of your numbers:

v1 = 1 metric drop of 2.303% (w/v) MB = 0.00005L
The final volume = v2 = m1v1/m2 = (2303/31985)(0.00005L)/(24/6397) = 9.5958333333333333333333333341607e-4L = ~0.96mL
The amount of water needed is 9.5958333333333333333333333341607e-4L - 0.00005L = 9.0958333333333333333333333341607e-4 L = ~0.91mL

So adding 1 drop of 2.303% (w/v) MB to 0.91mL water should give us ~0.96ml of diluted solution.
and with ~20 metric drops/mL you should have: ~ 19 drops @ 60mcg/drop

Those are real small numbers and it doesn't give us much final solution. So using 1mL for initial volume and your other numbers....

v1 = 1mL of our 2.303% (w/v) MB = 0.001L
The final volume = v2 = m1v1/m2 = (2303/31985)(0.001L)/(24/6397) = 0.019191666666666666666666666668422L = ~19.2mL
The amount of water needed is 0.019191666666666666666666666668422L - 0.001L = 0.018191666666666666666666666668L = ~18.2mL

So adding 1mL of 2.303% (w/v) MB to 18.2mL of water should give us ~19.2ml of diluted solution.
and with ~20 metric drops/mL you should get: ~ 384 drops @ 60mcg/drop

~~~~~~~~~~~~~~

If you notice the posts before this one, even the simple calculations were pretty close. Without knowing the Molar mass of MB or using these formulas, they would have arrived at basically the same answer given a 2.303% (w/v) solution has:

2.303 g solute in 100mL solution
or 0.02303g in 1mL
or 23.03mg in 1mL
or 23030mcg in 1mL

20 metric drops in 1mL (0.05mL/drop) - see http://en.wikipedia....i/Drop_(volume)

23030mcg / 20 drops = 1151.5mcg/drop

So there is ~ 1151.5mcg MB per metric drop of a 2.303% (w/v) MB solution

but we want 60mcg/drop. Our concentration is 19.1917 (1151.5 / 60) times too strong.

So going back to mL to recheck ... 60mcg/drop ~= 1200mcg/mL
(23030 / 1200) = 19.191666666666666666666666666667

Our 2.303% solution is 23030mcg in 1mL... but we need for it to be 23030mcg in ~19.2mL. So we add ~18.2mL of water to our existing 1mL of 2.303% solution.
and with ~20 metric drops/mL you should get: ~ 384 drops @ 60mcg/drop


edit:fixed line wraps

Edited by frankbuzin, 19 October 2009 - 07:45 AM.


#37 abelard lindsay

  • Guest
  • 873 posts
  • 228 ₮
  • Location:Mare Serenitatis Circumlunar Corporate Republic

Posted 19 October 2009 - 09:46 AM

Hi all! I'm one of the Methylene blue experimenters on the earlier thread. I've been taking it pretty regularly for a number of weeks now and have not had any bad effects. In fact, I've had a lot of good effects. Given the cheap price and what not I'm going to take this stuff indefinitely. Anyway, The way I currently take it is I put 6 to 7 drops of the 2% solution in a 1 liter San Pellegrino bottle and pour myself a small cup and drink it. If I drink it in the morning, the effects tend to last throughout the day. When I first got into this, I put one drop on my tounge and dyed my tounge a ridiculous blue color. After that, I switched to putting 1 drop in 1 liter of water and taking sips from it. After that I slowly upped the dosage. I don't think there's any benefit to more than the current dosage I'm taking.

#38 maxwatt

  • Guest, Moderator LeadNavigator
  • 4,953 posts
  • 1,627 ₮
  • Location:New York

Posted 19 October 2009 - 10:13 AM

Hi all! I'm one of the Methylene blue experimenters on the earlier thread. I've been taking it pretty regularly for a number of weeks now and have not had any bad effects. In fact, I've had a lot of good effects. Given the cheap price and what not I'm going to take this stuff indefinitely. Anyway, The way I currently take it is I put 6 to 7 drops of the 2% solution in a 1 liter San Pellegrino bottle and pour myself a small cup and drink it. If I drink it in the morning, the effects tend to last throughout the day. When I first got into this, I put one drop on my tounge and dyed my tounge a ridiculous blue color. After that, I switched to putting 1 drop in 1 liter of water and taking sips from it. After that I slowly upped the dosage. I don't think there's any benefit to more than the current dosage I'm taking.


The problem is getting a standard drop. There should be 20 per ml, but his can vary with the viscosity of the fluid and the size of the dropper. The standard 30 ml bottle with a medicine dropper should be pretty close to the standard

From a pharmacist's post in Sci.life-extension

fish methylene blue
is 2.303% w/v so that is 2.303 grams in 100cc of distilled purified
water. Take a ml or 1/100th = 23 mg / ml (1ml = 1 dropperful) .. Take
2 ml or 2 dropperfuls = 46mg , place it in 30ml water and you get a
dilution of 1.53 mg /ml. There 20 drops to a ml in a medicine
dropper, so 1.53 mg divided by 20 = .075 mg which is 75 microgram- we
only want 60mcg, so let's go back to the 2 dropperfuls X 60mcg/75mcg =
1.6 dropperful in 30 ml medicinal dropper bottle and qs to 30ml which
now gives the 60mcg per DROP!


In short, 1.6 ml of fish-store MB in 28.4 ml of distilled water, at 20 drops to the ml, one drop gives a 60 mcg dose. Or use Perrier. Whatever floats your boat.
To be precise one can buy measuring equipment, including tenths-of-a-milliliter accurate pipettes in a drug store, the section with medicine dispensers.

FWIW, methelene blue is one of a half dozen or so things that increase the cellular NAD/NADH ratio, along with things like resveratrol and CR, a phenomenon that has been associated with lie extension.

Edited by maxwatt, 19 October 2009 - 10:17 AM.
Spiling and gramer


#39 8lu3

  • Guest
  • 128 posts
  • 5 ₮

Posted 19 October 2009 - 02:07 PM

Again anyone feel free to correct me, but for 2.4%, you should dilute 1ml of MB with 20ml of water to get 60mcg per drop. :p

Makes it even easier actually


My MB comes with a 1ml plastic pipette, so that will make it easier to add to the 20ml of water.

Thank you

#40 8lu3

  • Guest
  • 128 posts
  • 5 ₮

Posted 19 October 2009 - 02:40 PM

Hi all! I'm one of the Methylene blue experimenters on the earlier thread. I've been taking it pretty regularly for a number of weeks now and have not had any bad effects. In fact, I've had a lot of good effects. Given the cheap price and what not I'm going to take this stuff indefinitely. Anyway, The way I currently take it is I put 6 to 7 drops of the 2% solution in a 1 liter San Pellegrino bottle and pour myself a small cup and drink it. If I drink it in the morning, the effects tend to last throughout the day. When I first got into this, I put one drop on my tounge and dyed my tounge a ridiculous blue color. After that, I switched to putting 1 drop in 1 liter of water and taking sips from it. After that I slowly upped the dosage. I don't think there's any benefit to more than the current dosage I'm taking.


Thank you for sharing your experience with MB.

When you say that you took sips of the MB in the San Pellegrino, did you finish the 1ltr bottle in a day or did the bottle last a few days?

Would you say that you are now getting more than the suggested 60mcg dosage in a day and are you taking the MB with anything else i.e nootropics?

Thank you

#41 Gerald W. Gaston

  • Guest
  • 529 posts
  • 58 ₮
  • Location:USA

Posted 19 October 2009 - 02:50 PM

...
From a pharmacist's post in Sci.life-extension

fish methylene blue
is 2.303% w/v so that is 2.303 grams in 100cc of distilled purified
water. Take a ml or 1/100th = 23 mg / ml (1ml = 1 dropperful) .. Take
2 ml or 2 dropperfuls = 46mg , place it in 30ml water and you get a
dilution of 1.53 mg /ml. There 20 drops to a ml in a medicine
dropper, so 1.53 mg divided by 20 = .075 mg which is 75 microgram- we
only want 60mcg, so let's go back to the 2 dropperfuls X 60mcg/75mcg =
1.6 dropperful in 30 ml medicinal dropper bottle and qs to 30ml which
now gives the 60mcg per DROP!


In short, 1.6 ml of fish-store MB in 28.4 ml of distilled water, at 20 drops to the ml, one drop gives a 60 mcg dose.
...


I saw that posted awhile back too and it is close.

whether we are talking about 36848mcg/1.6mL vs 1920mcg/1.6mL or 23030mcg/mL vs 1200mcg/mL the magic number is 19.1917
1.6mL * 19.1917 = ~30.7mL total solution
30.7mL - 1.6mL = 29.1ml of water to add.


Do it with the V1C1=V2C2 method and you get:

V2 = (((2303/31985)(0.0016))/(24/6397)) = 0.030706666666666666666666666666667L = ~30.7mL
Water to add is 0.030706666666666666666666666666667L - 0.0016L = 0.029106666666666666666666666666667 = 29.1mL

http://abacus.bates..../dilutions.html

#42 Gerald W. Gaston

  • Guest
  • 529 posts
  • 58 ₮
  • Location:USA

Posted 19 October 2009 - 03:04 PM

Again anyone feel free to correct me, but for 2.4%, you should dilute 1ml of MB with 20ml of water to get 60mcg per drop. :p

Makes it even easier actually


My MB comes with a 1ml plastic pipette, so that will make it easier to add to the 20ml of water.

Thank you



For 2.4%... and still using tritium's numbers for m2:

v2 = (2400/31985)(0.001L)/(24/6397)

v2 = (((2400/31985)*(0.001))/(24/6397)) = 0.02L = 20mL total solution
20mL - 1mL = 19mL water to add

#43 Gerald W. Gaston

  • Guest
  • 529 posts
  • 58 ₮
  • Location:USA

Posted 19 October 2009 - 04:52 PM

...
From a pharmacist's post in Sci.life-extension

fish methylene blue
is 2.303% w/v so that is 2.303 grams in 100cc of distilled purified
water. Take a ml or 1/100th = 23 mg / ml (1ml = 1 dropperful) .. Take
2 ml or 2 dropperfuls = 46mg , place it in 30ml water and you get a
dilution of 1.53 mg /ml. There 20 drops to a ml in a medicine
dropper, so 1.53 mg divided by 20 = .075 mg which is 75 microgram- we
only want 60mcg, so let's go back to the 2 dropperfuls X 60mcg/75mcg =
1.6 dropperful in 30 ml medicinal dropper bottle and qs to 30ml which
now gives the 60mcg per DROP!


In short, 1.6 ml of fish-store MB in 28.4 ml of distilled water, at 20 drops to the ml, one drop gives a 60 mcg dose.
...


I saw that posted awhile back too and it is close.
...


I saw that posted awhile back too and it is close.


And actually although the verbiage is a little off on how he arrives at the answer, the answer is correct.

V1 = V2*C2/C1
V1 = ((0.030*(24/6397))/(2303/31985)) = 0.0015631784628745115067303517151541L = ~1.6mL

0.030L - 0.0015631784628745115067303517151541L = 0.028436821537125488493269648284846 = ~28.4mL

#44 abelard lindsay

  • Guest
  • 873 posts
  • 228 ₮
  • Location:Mare Serenitatis Circumlunar Corporate Republic

Posted 20 October 2009 - 02:39 AM

Usually, my San Pellegrino bottles last a for 2-3 days. I take a bunch of nootropics. ALCAR, Piracetam (1/4 tsp), Aniracetam(1/4 tsp). I don't think it's particularly synergistic with any of these.

When you say that you took sips of the MB in the San Pellegrino, did you finish the 1ltr bottle in a day or did the bottle last a few days?

Would you say that you are now getting more than the suggested 60mcg dosage in a day and are you taking the MB with anything else i.e nootropics?

Thank you



#45 8lu3

  • Guest
  • 128 posts
  • 5 ₮

Posted 20 October 2009 - 12:28 PM

Usually, my San Pellegrino bottles last a for 2-3 days. I take a bunch of nootropics. ALCAR, Piracetam (1/4 tsp), Aniracetam(1/4 tsp). I don't think it's particularly synergistic with any of these.

When you say that you took sips of the MB in the San Pellegrino, did you finish the 1ltr bottle in a day or did the bottle last a few days?

Would you say that you are now getting more than the suggested 60mcg dosage in a day and are you taking the MB with anything else i.e nootropics?

Thank you



Thank you.

#46 BlueWay

  • Guest
  • 20 posts
  • 0 ₮
  • Location:Milky Way

Posted 29 June 2012 - 10:38 PM

I've read many, many posts about methylene blue dilution on this thread and many other threads here. It's very difficult, for me anyway, to follow as there are many different opinions about this.

Is there a kind soul reading this who can explain, in numbered step-by-step fashion, for the benefit of those of us here who are not chemists and have no medical degree, how to take a bottle of 2.303% methylene blue and get a 60mcg solution and also explain what to do with the solution once we have it (e.g., one drop from an eye dropper sublingually?; store the solution at room temperature for 3 days?, etc.)? It would be a great help to some of us. Please start by telling us the equipment we will need. Thank you!

#47 niner

  • Guest
  • 16,276 posts
  • 2,000 ₮
  • Location:Philadelphia

Posted 30 June 2012 - 03:11 AM

I've read many, many posts about methylene blue dilution on this thread and many other threads here. It's very difficult, for me anyway, to follow as there are many different opinions about this.

Is there a kind soul reading this who can explain, in numbered step-by-step fashion, for the benefit of those of us here who are not chemists and have no medical degree, how to take a bottle of 2.303% methylene blue and get a 60mcg solution and also explain what to do with the solution once we have it (e.g., one drop from an eye dropper sublingually?; store the solution at room temperature for 3 days?, etc.)? It would be a great help to some of us. Please start by telling us the equipment we will need. Thank you!


If you want to get the mitochondrial boost described by Ames and Atamna, 60mcg won't do it. You will need exactly one thousand times as much; 60 milligrams. If you want 60 mg of MB from a 2.303% solution, it's 2.6ml. Extract it with a graduated medicine dropper or pipette, and shoot it into your mouth. You could dilute it in whatever amount of water you want if you like. It will make your pee turn blue.

If you want the homeopathic 60 mcg dose, the easiest way is place a glass of pure water on the table, and just show it the bottle. Don't even open it; just hold the bottle of MB near the glass for a minute. Then shut your eyes and drink the water. You will feel awesome, and your pee will not turn blue.

I've tried a variety of MB doses, and ascribe all reports of activity at sub-milligram dose to the placebo effect. YMM, of course, V.

#48 protoject

  • Guest
  • 952 posts
  • 271 ₮
  • Location:Canada

Posted 30 June 2012 - 03:23 AM

If you want to get the mitochondrial boost described by Ames and Atamna, 60mcg won't do it. You will need exactly one thousand times as much; 60 milligrams.


Reference please Niner?? :)

#49 niner

  • Guest
  • 16,276 posts
  • 2,000 ₮
  • Location:Philadelphia

Posted 30 June 2012 - 03:32 AM

If you want to get the mitochondrial boost described by Ames and Atamna, 60mcg won't do it. You will need exactly one thousand times as much; 60 milligrams.


Reference please Niner?? :)


That's the dose used for Alzheimer's. The appropriate reference would be one of Atamna's papers, sorry it's late... but they're out there if you want to look. The 60mcg was just pulled out of a cocked hat by someone, and it caught on and became some sort of "Longecity Standard". It doesn't have any clinical or theoretical basis.

#50 MrHappy

  • Guest, Moderator
  • 1,815 posts
  • 405 ₮
  • Location:Australia

Posted 30 June 2012 - 10:00 AM

1mg is a noticeable dose for a lot of people. Even 60mcg x 3 gave me significantly increased vision, either via increased blood-flow or mitochondrial efficiency.

I have found a big difference between the effects from 'pet products', even between batches from the same vendor.

Edited by MrHappy, 30 June 2012 - 10:04 AM.


#51 protoject

  • Guest
  • 952 posts
  • 271 ₮
  • Location:Canada

Posted 30 June 2012 - 04:21 PM

Yeah, I also notice effects at less than 1 mg and even less than 100 mcg. I didn't actually read about any "increased blood flow" effects or anything like that but I felt an enhancement of blood flow similar to a sensation I get if i take a lot of phosphatidylcholine. It's like I can hear the blood swishing through my ears kind of but in a good way. It feels healthy. And it doesn't necessarily feel like a "metabolic rush" like some people talk about, it just feels like better blood flow and maybe a more constant blood pressure. But ya. Anyway. There are a lot of things I can say are placebo for myself but I didn't even expect this from MB... but I was always of the opinion as well that the 60 mcg dose was pulled straight out of someone's asshole... i mean REALLY WHAT'S THE SCIENCE BEHIND THIS?? Doesn't seem there is any... I feel it though.

#52 BlueWay

  • Guest
  • 20 posts
  • 0 ₮
  • Location:Milky Way

Posted 30 June 2012 - 10:37 PM

And so the best way to dilute 2.303% methylene blue to 1 mg or 60 mcg is to ...?

#53 MrHappy

  • Guest, Moderator
  • 1,815 posts
  • 405 ₮
  • Location:Australia

Posted 30 June 2012 - 11:05 PM

And so the best way to dilute 2.303% methylene blue to 1 mg or 60 mcg is to ...?


Here's a quick/rough method:
Get an insulin syringe to measure it out - 100 units is 1mL.

2.3% = 23mg/mL as a starting point.

20mL of water per 1mL of MB gets you a dilution where 1mL is close to 1.15mg/mL.

So to dose at close to 1 or 1.15mL, you take .9 or 1mL of the dilution in a glass of water.

FWIW, I'm toying around with 20mg doses at the moment and that seems to work quite well for energy and focus, etc. Seems to be clearing up a small fungal issue I had. No blue pee, either.
  • like x 1

#54 protoject

  • Guest
  • 952 posts
  • 271 ₮
  • Location:Canada

Posted 01 July 2012 - 05:25 PM

And so the best way to dilute 2.303% methylene blue to 1 mg or 60 mcg is to ...?



I put about 30 drips of MB from a 1mL medicine dropper into 591 mL of water [a water bottle size] and then i use a 1.25 mL measuring spoon [it's 1/4 a teaspoon] and scoop out the bluish water into a glass of water. Does this math work out right? Let's take a look:

23mg x 1.5 mL [the 30 drips is 1.5 dropperfulls for me and the dropperful is 1mL]
= 34.5 mg

34.5 mg divided by 591mL of water = 58 microcrams per mL of water.
x1.25 mL = 72.5 micrograms per scoop of blue water.

Edited by protoject, 01 July 2012 - 05:33 PM.


#55 protoject

  • Guest
  • 952 posts
  • 271 ₮
  • Location:Canada

Posted 01 July 2012 - 05:52 PM

Attached File  methylene blue.JPG   104.8KB   41 downloadsCheck out my visual aid. [I definitely could have used one] [attached as a JPG]

Edited by protoject, 01 July 2012 - 05:53 PM.

  • like x 1

#56 BlueWay

  • Guest
  • 20 posts
  • 0 ₮
  • Location:Milky Way

Posted 02 July 2012 - 02:31 AM

Thank you MrHappy and Protoject for the recipes. Outstanding visual aid, Protoject.

#57 protoject

  • Guest
  • 952 posts
  • 271 ₮
  • Location:Canada

Posted 02 July 2012 - 06:08 AM

ooops i forgot to type "591 mL water bottle" in the picture.. oh well! just remember use a 591 mL bottle... which is what most regular water bottles are... but it should say it right on the water bottle label.

#58 sbidl1

  • Guest
  • 4 posts
  • 0 ₮
  • Location:Australia

Posted 06 February 2013 - 05:19 AM

Is this right... I have 12mg/ml of methylene blue.
Which is 12000mcg per ml.
If I took 1ml (12000mcg) MB and put it in 200ml of water... The concentration would be 12000mcg per 200ml of water? So... To get that down to 60ug... I would take 1ml of that 200ml solution? Is this right?

#59 RWhigham

  • Member
  • 509 posts
  • 488 ₮
  • Location:United States
  • NO

Posted 15 March 2018 - 10:32 PM

Simplified dilution of the Kordon Methylene Blue - The bottle says "Add 5 tsp of concentrate to 3 gallons of water for 50 ppm". We don't want to make 3 gallons at once, so lets calculate the dilution ratio, scale the 5 tsp of concentrate down to 1 ml, and see how many oz of water it gives.

 

To make it easy I use the app  "Simply Convert Units Pro" to convert ml to oz and gal to tsp. 3 gallons = 2304 tsp.

 

                                                                            dilution ratio            oz of water for 1 ml of concentrate

  1. For 50 ug/ml: the dilution ratio is 2304 tsp/5 tsp = 460.8    460.8 ml = 15.58 oz of water
  2. For 60 ug/ml: the dilution ratio is (5/6)(460.8) = 384.0      384.0 mi = 12.9846 oz of water
  3. For 80 ug/ml: the dilution ratio is (5/8)460.8 = 288.0       288 ml = 9.738 oz of water
  4. For 100 ug/mL: the dilution ratio is (1/2)460.8 = 230.4       230.4 ml = 7.7908 oz of water

To make even fewer oz than indicated above, scale down the 1 ml of concentrate as follows:

Example:  To make 4 oz instead of 9.738 oz at 80 ppm,  use (4 oz / 9.738 oz) x 1 ml of concentrate =  0.41 ml

 

Result:   Add 0.41 ml to a partially filled 4 oz bottle, then top off the bottle with water  Now 1/4 tsp = 100 ug  (1/4 tsp = 1.25 ml)

 

Measuring the 0.41 ml:  I used a 1 ml "no dead space" insulin syringe (EasyTouch). First fill the syringe with 0.41 ml of water and note where the back of the plunger is located (at 0.51 in this case). The MB concentrate is so dark you will not be able to see the other side of the plunger. Then fill with 0.41 ml of concentrate by pulling the back of the plunger to the noted position.


Edited by RWhigham, 15 March 2018 - 11:00 PM.


sponsored ad

  • Advert
Click HERE to rent this advertising spot for SUPPLEMENTS (in thread) to support LongeCity (this will replace the google ad above).

#60 RWhigham

  • Member
  • 509 posts
  • 488 ₮
  • Location:United States
  • NO

Posted 16 March 2018 - 05:45 AM

Proof that Kordon Methylene Blue at 2.303 % by weight gives 50 ppm when diluted by 5 tsp in 3 gallons.

 

Hypothesis: 1 ml of solution = 1 g  same as 100% water (not exact but close enough)

 

2.303% is 2.303mg / 100mg = 23.03 mg / 1000mg = 23.03 mg/g = 23.03 mg/ml

5 tsp = 24.644 mg    from "Simply Convert Units Pro"
5 tsp MB concentrate contains  24.644 ml x  23.03 mg/ml = 567.565 mg of MB
3 gallon = 11,356.235 ml    from "Simply Convert Units Pro"
5 tsp / 3 gallon = 567.565 mg / 11,356.235 ml = 0.04998 mg/ml = 49.98 ug/ml = 49.98 ug/g = "50 ppm"
 

Edited by RWhigham, 16 March 2018 - 05:55 AM.

  • Informative x 1

sponsored ad

  • Advert
Click HERE to rent this advertising spot for SUPPLEMENTS (in thread) to support LongeCity (this will replace the google ad above).




Also tagged with one or more of these keywords: methylene blue

1 user(s) are reading this topic

0 members, 1 guests, 0 anonymous users